When showing a new growl in angularjs clear the old ones from view
When showing a new growl in angularjs clear the old ones from view I am working on growl.info() on angularjs and I have a question. How can I check if a growl exists in view (screen), when trying to add a new one? If a new one tries to be shown the previous one must be erased from screen. The code in controller is this: $scope.showInfo= function () { var info = "test"; growl.info(message.replace("{0}", info), { ttl: 50000 }); }; but note that ttl is important too. If no new growl tries to be shown, the first must live for a long period. Thank you in advance! 1 Answer 1 Firslty we add a public variable: $scope.growlMessge = null; and then we check if it has already a value (just to destroy it), before giving the new one $scope.showInfo= function () { if ($scope.growlMessage != null) { $scope.growlMessage.destroy(); } ...