Multi tool use

regex : get part of text from url data

I have many of this type of url :

http://www.example.com/some-text-to-get/jkl/another-text-to-get


I want to be able to get this :

["some-text-to-get", "another-text-to-get"]


I tried this :

re.findall(".*([[a-z]*-[a-z]*]*).*", "http://www.example.com/some-text-to-get/jkl/another-text-to-get")


but it's not working. Any idea ?

4 Answers
4

You can use a lookbehind and lookahead:

import re
s = 'http://www.example.com/some-text-to-get/jkl/another-text-to-get'
final_result = re.findall('(?<=.w{3}/)[a-z-]+|[a-z-]+(?=$)', s)


Output:

['some-text-to-get', 'another-text-to-get']


[a-z]

You could capture the 2 parts in a capturing group:

^https?://[^/]+/([^/]+).*/(.*)$

^https?://[^/]+/([^/]+).*/(.*)$

That would match:

^

https?://

://

[^/]+/

([^/]+)

.*

/

.*

(.*)$

$

Your matches are in the first and second capturing group.

Demo

Or you could parse the url, get the path, split by a / and get your parts by index:

/

from urlparse import urlparse

o = urlparse('http://www.example.com/some-text-to-get/jkl/another-text-to-get')
parts = filter(None, o.path.split('/'))
print(parts[0])
print(parts[2])


Given:

>>> s
"http://www.example.com/some-text-to-get/jkl/another-text-to-get"


You can use this regex:

>>> re.findall(r"/([a-z-]+)(?:/|$)", s)
['some-text-to-get', 'another-text-to-get']


Of course you can do this with Python string methods and a list comprehension:

>>> [e for e in s.split('/') if '-' in e]
['some-text-to-get', 'another-text-to-get']


You could capture it using this regular expression:

((?:[a-z]+-)+[a-z]+)

((?:[a-z]+-)+[a-z]+)

[a-z]+ match one or more character

[a-z]+

(?:[a-z]+-) don't capture in group

(?:[a-z]+-)

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