R Extract values from data frame with vectors


R Extract values from data frame with vectors



I hope my question is not a duplicate, but I really couldn't find what I need. I dived in dplyr and even did the data.table course from DataCamp, but I can't fix it. Maybe overlooking something?



I have this df:


set.seed(1964)
df<-data.frame(id = c( "XEY", "NZH", "DYE", "JNF", "LHH", "WNB"),
q_1 = sample(5,6, replace = TRUE),
q_2 = sample(5,6, replace = TRUE),
q_3 = sample(5,6, replace = TRUE),
q_4 = sample(5,6, replace = TRUE),
q_5 = sample(5,6, replace = TRUE))



So my df looks like this:



enter image description here



Next I have two vectors with id's (row-indicators) and q's (question numbers) like these:


id <- c("XEY", "DYE", "JNF", "DYE", "XEY", "LHH", "WNB", "JNF" )
question <- c("val_1", "val_1","val_3","val_3","val_3", "val_4", "val_4", "val_5")



I want to extract the values from the df using the two vectors to get an output like this:



enter image description here



I have tried a lot of things to extract the values, but I keep getting errors. I have tried things like:


df[id == (id[1]), (question[1])]
df[id == id[1], question[1]]



The strange thing is that the data.table package seems to accept the 'row-notation'. Because:


df[id == (id[1]),]



gives back the valuea for row "XEY":


id q_1 q_2 q_3 q_4 q_5
1: XEY 5 1 5 4 1



But how to do the trick for the right column notation using my vector?



Sorry for this very basic question, appreciate your help.





can you also manually construct a data.frame which indicates your desired output?
– tyumru
Jul 2 at 10:41





Something like this? The way of commenting differs very much from the way I can share info in the question: id <- c("XEY", "DYE", "JNF", "DYE", "XEY", "LHH", "WNB", "JNF" ) question <- c("val_1", "val_1","val_3","val_3","val_3", "val_4", "val_4", "val_5") value <- c(5, 1, 2, 1, 5, 2, 2, 3) output <- as.data.frame(cbind(id, question, value))
– Marlein
Jul 2 at 10:56



id <- c("XEY", "DYE", "JNF", "DYE", "XEY", "LHH", "WNB", "JNF" )


question <- c("val_1", "val_1","val_3","val_3","val_3", "val_4", "val_4", "val_5")


value <- c(5, 1, 2, 1, 5, 2, 2, 3)


output <- as.data.frame(cbind(id, question, value))




2 Answers
2



You can do that with tidyr.
I add stringsAsFactors=FALSE to your df to avoid a warning during the join.


set.seed(1964)
df<-data.frame(id = c( "XEY", "NZH", "DYE", "JNF", "LHH", "WNB"),
q_1 = sample(5,6, replace = TRUE),
q_2 = sample(5,6, replace = TRUE),
q_3 = sample(5,6, replace = TRUE),
q_4 = sample(5,6, replace = TRUE),
q_5 = sample(5,6, replace = TRUE),stringsAsFactors=FALSE)
id <- c("XEY", "DYE", "JNF", "DYE", "XEY", "LHH", "WNB", "JNF" )
question <- c("q_1", "q_1","q_3","q_3","q_3", "q_4", "q_4", "q_5")

library(tidyr)
df2 <- data.frame(id,question,stringsAsFactors=FALSE)
df %>% gather(k,Value,-id) %>% inner_join(df2,by="id") %>% filter(question==k) %>% arrange(question) %>%
select(-k)





Wauw! THANKS! i am going to study on your answer to grasp what you are doing, but it worked!!!
– Marlein
Jul 2 at 10:54



In base R you can do the following.


Value <- diag(as.matrix(df[match(id, df$id), sub("val", "q", question)]))
result <- data.frame(id, Question = sub("val", "q", question), Value)
result
# id Question Value
#1 XEY q_1 5
#2 DYE q_1 1
#3 JNF q_3 2
#4 DYE q_3 1
#5 XEY q_3 5
#6 LHH q_4 2
#7 WNB q_4 2
#8 JNF q_5 3



Edit.



After seeing the answer by @Nicolas2, with the use of inner_join, I have decided to give merge a try. But to do it I will need function melt from external package reshape2.


inner_join


merge


melt


reshape2


df2 <- data.frame(id, question = sub("val", "q", question))
df3 <- reshape2::melt(df, id.vars = "id")
names(df3)[2] <- "question"
result2 <- merge(df2, df3)
result2
# id question value
#1 DYE q_1 1
#2 DYE q_3 1
#3 JNF q_3 2
#4 JNF q_5 3
#5 LHH q_4 2
#6 WNB q_4 2
#7 XEY q_1 5
#8 XEY q_3 5



The result is the same, with a different row order.





Hi Rui. You too thanks a lot. I am going to study your solutions, am learning a lot today!
– Marlein
Jul 2 at 15:13






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