code breaker program in python is not working properly [closed]

Multi tool usecode breaker program in python is not working properly [closed]
enter code here
import random
digits = list(range(10))
random.shuffle(digits)
print(digits)
my_list = [str(item) for item in digits [:3]]
print (my_list)
digits = (''.join (my_list))
print (digits)
guesses = 0
while guesses <=3:
if(guesses == 3):
break
guess = input('What is your guess ? :- ' )
tmp = ''
for i in guess:
if i.isdigit():
tmp += i
guess = tmp[:3]
print(guess)
count = 0
for i in range(3):
for j in range(3):
if digits[i] == guess[j] :
#if i == j:
count = count + 1
exit()
if count == 3 :
print('found:',end = ' ')
print('YOU WON')
exit()
break
elif ((count>0) and (count <3)) :
print('near:',end = ' ')
else:
print('nope' , end = ' ')
guesses +=1
This question appears to be off-topic. The users who voted to close gave this specific reason:
1 Answer
1
You have an exit()
right after you calculate count
in the nested for
loops, so the program stop whenever the user enters a guess.
exit()
count
for
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What is the error you are getting?
– Almenon
Jul 1 at 17:46